Solve these show little steps if possible

a)

x≥3

b)

c)

y < 28

d)

x > 5/2

Step-by-step explanation:

a)

We have been given the following inequality;

4x-3≥9

add 3 to both sides of the equation,

4x-3+3≥9+3

4x≥12

divide both sides by 4,

x≥3

b)

We have been given the following inequality;

3(t+4)<5

we open the brackets on the left hand side,

3t + 12 <5

subtract 12 on both sides of the equation,

3t + 12 -12 <5-12

3t < -7

divide both sides by 3,

c)

We have been given the following inequality;

multiply both sides by 7,

2y < 56

divide both sides by 2,

y < 28

d)

5x + 4 > -3(x-8)

we open the brackets on the right hand side,

5x + 4 > -3x + 24

add 3x to both sides of the inequality,

5x + 4 + 3x > -3x + 24 + 3x

8x + 4 > 24

subtract 4 on both sides,

8x + 4 - 4 > 24 - 4

8x > 20

divide by 8 on both sides,

x > 5/2

Ithink the answer is: it is likely.

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%