Find the value of x if y =1/4x and 5x-8y=33

x=11

Step-by-step explanation:

y= 1/4x

5x-8y=33

5x-8(1/4x)=33

x=11

11

Step-by-step explanation:

Given that ,

⇒ y = 1/4x and

⇒ 5x - 8y = 33

We can write 1st equation as ,

⇒ 4y = x

Put x = 4y in 2nd Equation ,

⇒ 5*4y - 8y = 33

⇒ 20y - 8y = 33

⇒ 12y = 33

⇒ y = 33/12

Put this in 1st ,

⇒ 33/12 = 1/4 x

⇒ x = 33/12 × 4

⇒ x = 33/3

⇒ x = 11 .

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length