If alpha and beta are the zeroes of the polynomial f(x)=x2- p(x+1) - c show that (alpha+1) (beta +1) = 1-c

see explanation

Step-by-step explanation:

Given

f(x) = x² - p(x + 1) - c

     = x² - px - p - c ← in standard form

with a = 1, b = - p and c = - p - c

Given that α and β are the zeros of f(x), then

α + β = - and αβ = , thus

α + β = - = p , and

αβ = = - p - c

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(α + 1)(β + 1) ← expand factors

= αβ +α + β + 1 ← substitute values from above

= - p - c + p + 1

= - c + 1 = 1 - c ← as required

i think this could be a possible answer (1 / 84) -1

good luck! : d

this doesn't make sense lol