Does the midpoint bc lie on line ag? why or why not?

  see below

Step-by-step explanation:

Put the (x, y) values of point F into the equation for line AG and see if they work:

  y = (b/(a+c))x

For (x, y) = (a+c, b), this is ...

  b = (b/(a+c))(a+c) = b·(a+c)/(a+c) = b·1 = b . . . . . a true statement

Yes, F lies on line AG.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

its 50 miles away from the starting point