The number of bacteria in a petri dish triples every month. if the dish started with 2500 bacteria how much will be in ten months?

Below

Step-by-step explanation:

The dish had intially 2500 bacteria. The bacteria triples every month.

So after a month the number will be 7500 =>(2500×3)

So let 2500 be the n0 and 7500 be n1

● n1 = 3×n0

Following the same way we get:

● n2= 3× n1

● n3 = 3× n2

If we kept repeating the same process we will get:

● n9 = n8 × 3

n9 is the number of Bacteria during the 10th month

let's calculate n9.

● n9 = n8 × 3

● n9 = n0 × 3^10

● n9 = 2500 × 3^10

● n9 = 147 622 500

● n9 = 1.476225 ÷ 10^8

3x^3-x^2+6x-9

answer: the common difference is -0.10