Find x and h in this trinomial right angle

Step-by-step explanation:

Set up the Pythagorean Equation for the two triangles

x^2 + h^2 = 4^2  = 16

(x + 6)^2 + h^2 = 8^2 = 64

x^2 +    h^2 = 16                        Subtract. That will get rid of h^2

(x + 6)^2 - x^2 = 64 - 16            Expand the brackets. combine the right.

x^2 + 12x+36 - x^2 = 48           Combine

12x + 36 = 48                            Subtract 36 from both sides

12x +36 -36 = 48-36                 Combine

12x = 12                                      Divide by 12

12x/12 = 12/12

x = 1

x^2 + h^2 = 4^2

1^2 + h^2 = 16

h^2 = 15

h = sqrt(15)  

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier