Suppose that one student is randomly selected during lunch time. what is the experimental probability if students the brought lunch from house is 55 and students that order school lunch is 45

p(A) = 0.55

p(b) = 0.45

Step-by-step explanation:

Experimental probability =

total students = 55 + 45   ⇒ 100

let A be the probability that students brought lunch from house = ⇒ 0.55

let B be the probability that students order school lunch = ⇒ 0.45

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

brandon has 4344 video games.  

step-by-step explanation

7373 - 2929 = 4344

pls let me know if it was correct