The length of a rectangle is 24 units. can the perimeter x of the rectangle be 60 units when its width y is 11 units? a. no, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y b. no, the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y c. yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 48 d. yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 24

A

Step-by-step explanation:

The formula for the Perimeter of a rectangle is P = 2W + 2L.

Let's equate this to 60 units and substitute 11 for W and 24 units for L:

2(11 units) + 2(24 units) = 22 units + 48 units = 70 units.  NO (Answer A)

answer: do you still need this?

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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