Sandy mixed together 9 gallons of one brand of juice and 8 gallons of a second brand of juice which contains 48% real fruit juice. find the percent of real fruit juice in the first brand if the mixture contained 30% real fruit juice.

a) 18%

b) 140%

c) 180%

d) 14%

D) 14%

Step-by-step explanation:

Let the percent of the real fruit in the first brand = x

Given that number of gallons of  real fruit in the first brand = 9 gallons

Given that percent of the real fruit in the second brand = 48%

Given that number of gallons of  real fruit in the second brand = 8 gallons

Given that  percent of the real fruit in the mixture = 30%

then number of gallons of  real fruit in the mixture = (9+8) = 17 gallons

Then we get equation:

[x% of 9 gallons] + [48% of 8 gallons] = [30% of 17 gallons]

9x+48(8)=30(17)

9x+384=510

9x=510-384

9x=126

x=126/9

x=14

Hence final answer is D) 14%

b and c

step-by-step explanation: