How can you determine that a point lies on the perpendicular bisector of ma ¯ ¯ ¯ ¯ ¯ ¯ ¯ with endpoints m(−2, 4) and a(−6, −2)?

Are there options, I’d Love to help you, but I do best w options. Good luck and have a great day

You can find the perpendicular bisector of MA and then plug in the point.

Step-by-step explanation:

To find the perpendicular bisector of MA, you have to go through a 4 step process.

1. Find the midpoint of MA

2. Find the slope of MA

3. Find the perpendicular slope to the slope of MA.

4. Substitute in your midpoint into the equation and solve for the y-intercept.

Plug in your point into the equation and see if it works out.

You'll have to do the actual work yourself though!

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)