Solve the equation for the interval

x=0,3π/2,π

Step-by-step explanation:

Given

sin^2  x+sin⁡x=0

sin x is a common factor

so,

sin⁡x (sin⁡x+1)=0

We can put both factors one by one equal to zero

sin⁡x=0

x=  sin^(-1)⁡0

sin⁡x  is zero at 0 and π

x=0,π

sin⁡x+1=0

sin⁡x= -1

x=  sin^(-1)⁡(-1)

sin is -1 for 3π/2

So,

x=3π/2

So,

x=0,3π/2,π

the answer is 1 becuz if it were 1.0 that would rip apart the entire so ya. : )

~potato.

copyright potato 2019.

the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

the root or roots of a polynomial are the values of the variable that makes the polynomial equal to 0. we can find the roots of a polynomial making the expression equal to 0 and then, isolating the variable (it it has just one variable).

for example, given the following polynomial:

the root or zero of the polynomial, can be found by making the expression equal to 0, and then, isolating the variable, so, finding the root we have:

therefore, we have that the root of the polynomial is equal to 2.

we must remember that the number of roots that a polynomial can have, will depend on the degree of the polynomial, a first degree polynomial have will have one single root, a second degree polynomial (quadratic expression) may have two roots and so.

hence the correct option is:

b. a value of the variable that makes the polynomial equal to zero.

have a nice day!