8s-10=27-(3s-7) what does “s” equal?

s = 4

Step-by-step explanation:

Solve for s:

8 s - 10 = 34 - 3 s

Add 3 s to both sides:

8 s + 3 s - 10 = (3 s - 3 s) + 34

3 s - 3 s = 0:

8 s + 3 s - 10 = 34

8 s + 3 s = 11 s:

11 s - 10 = 34

Add 10 to both sides:

11 s + (10 - 10) = 10 + 34

10 - 10 = 0:

11 s = 34 + 10

34 + 10 = 44:

11 s = 44

Divide both sides of 11 s = 44 by 11:

(11 s)/11 = 44/11

11/11 = 1:

s = 44/11

The gcd of 44 and 11 is 11, so 44/11 = (11×4)/(11×1) = 11/11×4 = 4:

 s = 4

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5