Show that (x-1)(x+2)(x+3) can be written in the form ax^3+bx^2+cx+d

x³ + 4 x² + x - 6

Step-by-step explanation:

( x - 1 ) ( x + 2 ) ( x + 3 )

( x - 1 ) ( x + 2 ) = x² + 2 x - 1 x - 2 = x² + x - 2

( x² + x - 2 ) ( x + 3 ) = x³ + 3 x² + x² + 3 x - 2 x - 6 = x³ + 4 x² + x - 6