Cuales son las dimensiones de un rectángulo con un perímetro igual a 578 pulgadas, si su largo es 6 pulgadas menos que 4 veces su ancho

The dimensions of rectangle are 230 in by 59 in

Step-by-step explanation:

The question in English is

What are the dimensions of a rectangle with a perimeter equal to 578 inches, if its length is 6 inches less than 4 times its width?

Let

x> the length of rectangle

y> the width of rectangle

we know that

The perimeter of rectangle is equal to

P=2(x+y)

P=578 in

so

578=2(x+y)

289=x+y > equation A

x=4y-6 > equation B

substitute equation B in equation A

289=(4y-6)+y

5y=295

y=59 in

Find the value of x

x=4y-6 > x=4(59)-6=230 in

therefore

The dimensions of rectangle are

230 in by  59 in

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x