Ted and millicent write articles for an online magazine. the table gives the number of new followers the two gained in each of the last 10 days.

ted millicent
101 88
77 80
65 92
82 75
113 120
55 61
66 101
73 78
88 83
91 99

the mean absolute deviation of ted’s data is . the mean absolute deviation of millicent’s data is . comparing the mean absolute deviations for ted’s and millicent’s data sets indicates that ted’s data is generally varied than millicent’s data.

Here we need to calculate the mean deviation of both sets, and see wich one is more varied, where the mean data is directly related with the distance of each point of the set to the mean of the set.

The mean deviation can be calculated as:

∑Ixₙ - XI/n

where xₙ is each value, X is the mean of all the values, and n is the amount of values (in this case is 10 for both sets of data)

Now, using this equation we can calculate both mean deviations:

For Ted it is 13.9

for Millicent it is 12.3

The mean deviation of Ted is bigger, so Ted's data is more varied than the one of Millicent.

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13

i have no idea just need points sorry

step-by-step explanation: