Parking lot a has twice as many cars as parking lot b. after 10 cars draw away from parking lot a, and 13 cars moved from parking lot a to parking lot b, parking lots have the same amount of cars. how many cars were there in each parking lot?

The original number of cars in parking Lot A was 72 cars and the original number of cars in parking Lot B was 36 cars

Step-by-step explanation:

Let

x> original number of cars in parking Lot A

y> original number of cars in parking Lot B

we know that

x=2y > equation A

(x-10-13)=y+13 > equation B

substitute equation A in equation B and solve for y

(2y-10-13)=y+13

(2y-23)=y+13

2y-y=13+23

y=36 cars

Find the value of x

x=2y > x=2(36)=72 cars

therefore

The original number of cars in parking Lot A was 72 cars

The original number of cars in parking Lot B was 36 cars

b

step-by-step explanation:

the answer would be 150 books

step-by-step explanation:

if you divide 300 by 2 you will get 150