8is the base and 3/4

part a: what is the area of the parallelogram? show your work. (5 points)

part b: how can you decompose this parallelogram into two triangles? if this parallelogram was decomposed into two triangles, what would be the area of each triangle? (5 points)

Part A: 6 Part B: Put a line from the top right corner to the bottom left corner. Each triangle's area would be 3.

Step-by-step explanation:

PART A

The formula to find the area for a parallelogram is A = bh (Area = base · height)

A = bh

A = 8 · 3/4

A = 6

PART B

Draw a parallelogram if you need to show work and then just connect the top right corner and the bottom left, or top left to bottom right. If 6 (area of the parallelogram) ÷ 2 (since there is two triangles) = 3, then the area of the triangles has to be 3.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?