Aline segment has endpoints at 3,2 and 2,-3 which reflection will produce an image with endpoints at 3,-2 and 2,3

The reflection is across the x-axis

Step-by-step explanation:

* Lets revise the reflection

- If point (x , y) reflected across the x-axis

∴ Its image is (x , -y)

- If point (x , y) reflected across the y-axis

∴ Its image is (-x , y)

- If point (x , y) reflected across the line y = x

∴ Its image is (y , x)

- If point (x , y) reflected across the line y = -x

∴ Its image is (-y , -x)

* Now lets solve the problem

∵ The endpoints of a line segment are (3 , 2) and (2 , -3)

∵ The image of the endpoints after the reflection are (3 , -2) and (2 , 3)

* Lets study the change

# The x-coordinates of the points are 3 and 2

# The x-coordinates of the images are 3 and 2

# The y-coordinates of the points are 2 and -3

# The y-coordinates of the images are -2 and 3

- The change is in the signs of the y-coordinates

∴ The reflection is across the x-axis

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

pls mark as brainliest

yes

step-by-step explanation: