What is a1 for the geometric sequence for which a8= -3584 and a3 = 112 ?

The first term is 28.

Step-by-step explanation:

Given: 8th term of Geometric sequence ,

and 3rd term of Geometric Sequence,

We have to find First term of given geometric Sequence.

Let a be the first term of geometric sequence.

We know that,

So,

So, 3rd term = 112

a × (-2)² = 112

a = 112 / 4

a = 28

Therefore, The first term is 28.

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204