Given the vector v has an initial point (-2,-6) and a terminal point of (1,2) write vector v as a linear combination of the standard unit vector i and j.

v=3i+8j

Step-by-step explanation:

The given the vector v has an initial point (-2,-6) and a terminal point of (1,2).

To find the components of vector v, we subtract the terminal points from the initial point to obtain.

v=<1,2>-<-2,-6>

v=<1--2,2--6>

v=<1+2,2+6>

v=<3,8>

As a linear combination of the standard unit vectors.

v=3i+8j

sin3a=12/15

step-by-step explanation:

since one side was multiplied by 3 the other side must also be multiplied by 3.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18