What is the distance between (10, 6) and (-2, -3)

15 units.

Step-by-step explanation:

The distance between the points (x1, y1) and (x2, y2) is

√(x1-y1)^2 + (y1-y2)^2))

So here it is:

√(10- -2)^2 + (6- -3)^2)

= √(144+81)

=  √225

= 15.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

answer: 1, 3 and 5 are correct

step-by-step explanation: