Me. i'm so desperate not even my group chat is

5 between Martin's place and the school

Step-by-step explanation:

I don't know if you can draw a diagram from by directions, but you can try. It will help you to see the problem.

Draw

Draw a line that looks like this on your paper.

<:

school         X        Martin's place

Now draw a line going upwards from the arrow head.

∧                 Haley's place.

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<:

school       x      Martin's place

Label the distance from the school to Haley's place as 12

I can't draw a line between martin's place and Haley's but you can. Label it as 13

So the givens are

c = distance between Haley's place and Martin's = 13

b= distance from the school to Haley's is 12

a = ? Distance from Martin't and the school = x

Formula

c^2 = a^2 + b^2

Solution

13^2 = 12^2 + a^2

169 = 144 + a^2          Subtract 144 from both sides.

169 - 144 = 144 - 144 + a^2

25 = a^2

sqrt(25) = sqrt(a^2)

a = 5              

-14 is the answer

hope this : ))

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step-by-step explanation: