Find the standard form of the equation of the parabola with a focus at (3, 0) and a directrix at x = -3.
a. y = 1/12 x^2
b. -12y = x^2
c. x = 1/12 y2
d. y^2 = 6x

the answer would be c:   ax + b = ax + c

step-by-step explanation:

it is not that hard all u have to do is plot the graph

step-by-step explanation:

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)