Given vector u = (6,-4) and the graph of vector v, find v - 2u and express the result of terms in i and j

0i + 10j, or just 10j

Step-by-step explanation:

Vector u = <6, -4> and vector v = <12, 2>.

We are to find v - 2u, which is:

<12, 2> - 2<6, -4>.  We combine x components and y components to obtain:

<12-12, 2+8>, or <0, 10>.

In terms of i and j, that'd be 0i + 10j, or just 10j.

v-2u=10j

Step-by-step explanation:

The component of vector v, are

u=<6,-4>

From the graph; vector u, has components.

v=<12,2>

We perform the subtraction;

v-2u=<12,2>-2<6,-4>

We multiply out the scalar to get:

v-2u=<12,2>-<12,-8>

This implies that;

v-2u=<12-12,2--8>

v-2u=<0,10>

v-2u=0i+10j

v-2u=10j

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

answer:

step-by-step explanation: