Mathematics, 30.10.2019 13:31, izayahclark5123
Find the vertex, focus, directrix, and focal width of the parabola.
-1/16x^2 = y
a. vertex: (0, 0); focus: (0, -4); directrix: y = 4; focal width: 16
b. vertex: (0, 0); focus: (-8, 0); directrix: x = 4; focal width: 64
c. vertex: (0, 0); focus: (0, 4); directrix: y = -4; focal width: 4
d. vertex: (0, 0); focus: (0, -4); directrix: y = 4; focal width: 64
Answers: 3
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Find the vertex, focus, directrix, and focal width of the parabola.
-1/16x^2 = y
...
-1/16x^2 = y
...
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