If tanø = 3/4, find sinø

a. sinø=1/2

b. sinø = 3/5

c. sinø = 2

d sin ø = 8/5

This is some information I have gathered to help you since I cannot answer this directly sin θ + (cot θ)(cos θ)  

= sin θ + (cos θ / sin θ)(cos θ)  

= sin θ + cos² θ / sin θ  

Since cos² θ = 1 - sin² θ,  

= sin θ + (1 - sin² θ) / sin θ  

= sin θ + 1 / sin θ - sin θ  

= 1 / sin θ  

= csc θ ∎ Sin(x) = tan(x) / [sqrt(1 + tan^2(x)]  

Sin(theta) =3/4 / sqrt[1 + .75^2]

Sin(theta) =0.75 / sqrt[ 1.5625 ]

Sin(theta) =0.75 / 1.25

Sin(theta) = 0.60

95.03 is the answer. hope this !