![\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{-6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-6-(-7)}{-8-(-5)}\implies \cfrac{-6+7}{-8+5}\implies \cfrac{1}{-3}\implies -\cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-7)=-\cfrac{1}{3}[x-(-5)]\implies y+7=-\cfrac{1}{3}(x+5)](/tpl/images/0349/8457/cc6c0.png)
![\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_2=m(x-x_2) \\\\ \cline{1-1} \end{array}\implies y-(-6)=-\cfrac{1}{3}[x-(-8)]\implies y+6=-\cfrac{1}{3}(x+8)](/tpl/images/0349/8457/b682b.png)
use the given conditions to write an equation for the line in point-slope form.
passing t...
Mathematics, 28.10.2019 20:31, amya92
use the given conditions to write an equation for the line in point-slope form.
passing through (-5, -7) and (-8, -6)
a) y− 7 = −13(x−5) or y −6 = −13(x−8)
b) y+7= −13(x+8) or y+6 = −13(x+5)
c) y+7 = −13(x+5) or y+6 = −13(x+8)
d) y+7 = −13(x+5) or y +6 = −13(x+7)
Answers: 1
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