Compare the three functions below. which has a greater period? a) y = 3cos(2x+1), b) y=5cos(4x +8), and c) y=cos(2x+4) (4.3)

Step-by-step explanation:

Given functions are

A) y = 3cos(2x+1), B) y=5cos(4x +8), and C) y=cos(2x+4) (4.3)

or we can rewrite :

A) y = 3cos(2x+1), B) y=5cos(4x +8), and C) y=(4.3)cos(2x+4)

We need to find their periods which is basically (2pi/coefficient of x) of  the given cosine function.

So the period of given choices are:

A) , B) , and C)

or

A) , B) , and C)

Greatest of them is

So the correct choice is A) y = 3cos(2x+1) and C) y=cos(2x+4) (4.3)

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

step-by-step explanation:

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