When a line is parallel to another, it means they have the same slope. The equation of the line is y=my+b where m=slope. Our original slope is -2, and we need this line to pass through the points (2,2). So we simply plug the information in the point slope formula which says
y-y1=m(x-x1) where m=-2, x1=2, and y1=2
Y-2=-2(x-2)... I am going to destitute the -2 into the x and 2.
Y-2=-2x+2 now I am going to isolate the y to put it in y=my+b form by adding 2 to both sides and we see that it cancels on the left.
Y=-2x+4 I believe should be your answer but is not there. Further it should be noted that there must be a typo either in the answer choices, or in the wording of the question because this equation does not pass through (2,2)
The equation in slope-intercept form is y=-2x+6.
The equation in standard form is 2x+y=6.
The equation in point-slope form is y-2=-2(x-2).
The slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.
Parallel lines will have the same slope and different y-intercept.
Anyways the slope of y=-2x+1 is -2.
So the equation of our line we are looking for is -2.
So we know our equation is in the form y=-2x+b.
We must inf b using y=-2x+b with (x,y)=(2,2).
y=-2x +b with (x,y)=(2,2)
Add 4 on both sides:
The equation is y=-2x+6.
Now it didn't say what form it wanted.
There are some forms I can give you like standard and point-slope form.
There is also general form but it is not too much different from standard form.
Standard form is ax+by=c where a,b, and c are integers if possible.
Point-slope form is y-y1=m(x-x1) where (x1,y1) is a point on the line and m is the slope.
So let's go for standard form (ax+by=c) first:
add 2x on both sides:
This is standard form because it is in the form
Ok we know point (2,2) is on our line and we also know we have slope,m, is -2.
Point-slope form is
Now we put it all together using the slope m=-2 and the y intercept of 6
We know the slope of the given equation is -2. A parallel line must have the same slope as the original function. So if we plug in the coordinates and the slope into the point slope formula we get y=-2x +6
y = mx + b
slope(m) = -2
(2,2)x = 2 and y = 2
now sub into th formula and find b, the y int
2 = -2(2) + b
2 = -4 + b
2 + 4 = b
6 = b
so ur parallel equation is : y = -2x + 6 <== or 2x + y = 6depending on what form u need the equation in