Solve the equation of e^x-2=(1/e^6)^x+3.

x = -16/7

Step-by-step explanation:

The equation as written reduces to finding the solution to a 7th-degree polynomial. The one real solution, found using a graphing calculator, is ...

x ≈ 1.60945071137

Since this is beyond the scope of most algebra courses, we suspect you want the solution to ...

e^(x-2) = (1/e^6)^(x+3)

x -2 = -6(x +3) . . . . . . . . take the natural log of both sides

x -2 = -6x -18 . . . . . . . . . eliminate parentheses

7x -2 = -18 . . . . . . . . . . . add 6x

7x = -16 . . . . . . . . . . . . . add 2

x = -16/7

the amount you'd have after the work is $1.55

step-by-step explanation:

you subtract 95% from $31.

c

step-by-step explanation:

at least i think its