It was 9/20 ..
a math class has 9 girls and 1 boy in the seventh grade and 2 girls and 2 boys in the eighth grade. the teacher randomly selects a seventh grader and an eighth grader from the class for a competition. what is the probability that the students she selects are both girls?

write your fraction in simplest form.

Step-by-step explanation:

We want probability that 1st is girl AND 2nd is girl as well.

In probability "AND" means multiplication and "OR" means "addition".

We find the probabilities separately and multiply them together, since "AND".

=9/10

=2/4

P(both girls) = 9/10 * 2/4 =9/20

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752