(-9,-35) and (2,9) are two anchor points on the trend line, then find the equation of the line

the desired equation is y = 4x + 1

Step-by-step explanation:

As we move to the right from (-9, -35) to (2, 9), x increases by 11 and y increases by 44.  Thus, the slope of the line in question is

m = rise / run = 44/11 = 4.

Using the slope-intercept form of the equation of a straight line, we substitute 4 for m, 2 for x and 9 for y, obtaining:

y = mx + b →  9 = 4(2) + b.  Thus, b = 1, and the desired equation is

y = 4x + 1

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: -8.2562234e+13