The graph of y= 6cos (x-2) - 3 is obtained by shifting the graph of y=6 cos x-3 horizontally 3 units to the right. true or false?

false.

Step-by-step explanation:

Given the function g(x) = f(x − k), can be sketched f(x) shifted k units horizontally. if k is negative, the function is shifted k units to the left.

Given the function g(x) = f(x) + k, we can say that the function is translated vertically upwards k times. If k is negative, the function is translated vertically downwards k times.

In this case, the function is translated two units to the right and 3 units down because the number "-3" is negative.

So it's false. The graph is translated three units downwards and 2 units to the right.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation:

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)