Solve for x.
y=4+bx^2
a) x=±y−4b√
b) x=y−42b
c) x=y−4b
d) x=±y−4√b

± = x

Step-by-step explanation:

to solve y = 4 + bx², we want x alone, so lets subtract 4 from both sides to start

y - 4 = bx² < now divide both sides by b to get x alone

= x² < we can square root both sides to get rid of the x² in the equation

± = x

the equation above is our answer. looking at the answer choices, they look a bit messed up, but I would have to say the answer is A if that line above the b is a division symbol

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)