Which values of p and q result in an equation with exactly one solution?
2x+q=px−31

a. q=−2 and p=2
b. q=31 and p=2
c. q=−31q, equals, minus, 31 and p=-2p=−2p, equals, minus,
d. q=-31 and p=2

C. Q=−31, P = -2

Step-by-step explanation:

2x+Q = Px−31

A. Q = −2 and P=2

2x+Q=Px−31

2x - 2 =2x - 31

0x = -29

0 ≠ -29 : NO SOLUTION

B.Q=31 and P=2

2x+Q=Px−31

2x + 31 = 2x - 31

0x = -62

0 ≠ -62 : NO SOLUTION

C. Q=−31, P = -2

2x+Q=Px−31

2x - 31 = -2x - 31

4x = 0

 x = 0 : ONE SOLUTION

D. Q=-31 and P=2

2x+Q=Px−31

2x - 31 = 2x - 31

0x = 0

0 = 0: Infinitely many solutions

C. Q=−31, P = -2

42

step-by-step explanation:

256/6=42

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1