If 'f(x)=x^2-18' and 'g(x)=(x-9)^(-1)(x+9)', find 'g(x)*f(x)
a. (x+9)^2
b. (x-9)^2
c. 2(x+9)
d. (x+9)(x-9)

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

step-by-step explanation:

graph using a few selected

x         y

-1       15

0         6

1         2.4

2       0.96

on the middle line

step-by-step explanation:

1/5=50

165.75 years

p.s. this question was already   asked on/p>

step-by-step explanation: