The slop-intercept form of the equation of a line that passes through points (-2,-13) is y=5x-3 what is the point slope form of the equation of the equation for this line

y + 13 = 5(x + 2)

Step-by-step explanation:

y=5x-3 what is the point slope form of this equation?

The point-slope form looks like y - k = m(x - h), where (h, k) is the given point and m is the given slope.

Here the given point is (-2, -13).  Therefore, the desired equation is:

y -(-13) = 5( x - [-2] ), or

y + 13 = 5(x + 2)

Step-by-step explanation:

The given function passes through (-2,-13).

The slope-intercept form of this equation is .

This implies that; the slope of the given function is;

The point-slope form of this function is given by the formula;

We have

We substitute the point and the slope into the function to obtain;

hi there

the slope is 1/3.

this is because from the y-intercept, you go up one, and you go to the right three, to get to the next exact point on the graph. this is known at the “rise over run.”

p.s. (if you need it).your y-intercept is -2, because that is the point on the graph where the line crosses the y-axis.

hope that : )