The equation v(x)=32500(0.92)^x how much more is the truck worth after two years than after three years

the difference:  $2,192.64

Step-by-step explanation:

After 1 year, the truck has lost 8% of its value:  v(x) = $32,500(0.92)^1, or

$29,900.

After 2 years, v(x) = $32,500(0.92)^2, or $27,500.  Finally, after 3 years,

v(x) = $32,500(0.92)^3 = $25,307.36.

Subtracting $25,307.36 (the value after 3 years) from $27,500 (the value after 2 years) yields the difference:  $2,192.64

(x+3)(x+7)

step-by-step explanation:

just sum

10 + 10 = 20