The clock in our classroom has a radius of 9 inches. if its 4: 00, find the arc length and area of the sector for this time.

6pi; 27pi

Step-by-step explanation:

Since 4:00 is 120 degrees on a clock, then it is 120/360 or 1/3 of the clock. Now let’s find the arch length! Since the radius of the clock is 9, then the circumference will be 18pi. Since 1/3 of the clock is 4:00, then the arc length is 1/3 of the circumference. SO the arc length is 6pi.

Now let’s find the area of the sector. Since the radius is 9, then the area is 81pi. So 1/3 of that is 27pi.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

8/k

step-by-step explanation: