The formula for determining the frequency, f, of a note on a piano is f=440(2)^h/12 where h is the number of half-steps from the a above middle c on the keyboard. a note is six half-steps away from the a above middle c. the frequency of the a above middle c is 440 hz. how much greater is the frequency of the new note compared with the frequency of the a above middle c?
a)29.3%
b)41.4%
c)70.7%
d)182.3%

41.4%

Step-by-step explanation:

The formula for determining the frequency:  --A

where h is the number of half-steps from the A above middle C on the keyboard.

A note is six half-steps away from the A above middle C.

Now we are supposed to find How much greater is the frequency of the new note compared with the frequency of the A above middle C?

Now initially there is no half steps .

So, substitute h =0

Now we are given that A note is six half-steps away from the A above middle C

So, substitute h =6

Now To find change percentage

Formula:

Hence  the frequency of the new note is 41.4% greater with the frequency of the A above middle C.

answer: download photomath it's legit.

step-by-step explanation:

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: