The figure below is a net for a triangular prism. side a = 22 feet, side b = 14 feet, side c = 13 feet, side d = 13 feet, and side e = 19 feet. what is the surface area of this figure?

a. 1,194 square feet
b. 908 square feet
c. 1,172 square feet
d. 1,216 square feet

the answer is 1,194

Step-by-step explanation:

what you want to do is find the area of 2 triangles and 3 rectangles

area of 1st rectangle

1 = ae

=(22 ft) (19 ft)

=418 sq. ft.

area of 2nd rectangle

2 = ab

=(22 ft.) (14 ft.)

=308 sq. ft.

area of 3rd rectangle

3=ad

=(22 ft.) (13 ft.)

=286 sq. ft.

area of 1st triangle

Area of triangle =  1/2 cb

=1/2 (13ft) (14ft)

= 1/2 (182 sq. ft)

=91 sq. ft.

***this would be the same for 2nd triangle*** 91 sq ft.

Next add all areas together to get the total surface area

Total surface area = ae + ab + ad + 2 (1/2 cb)

= 418 sq. ft + 308 sq. ft. + 286 sq. ft. + 2(91 sq. ft)

=418 + 308 + 286 + 182

= 1,194 sq. ft.

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.