Scores on a test are normally distributed with a mean of 110 and a standard deviation of 19. what percentage of scores are greater than 167?

a. 0.15%
b. 0.3%
c. 99.7%
d. 99.85%

B.

Step-by-step explanation:

Apply the 68-95-99.7 rule

The rule supposed that;

68% of the data in a standard normal distribution falls within 1 standard deviation of the mean.

95% of the data in a standard normal distribution falls within 2 standard deviation of the mean.

99.7% of the data in a standard normal distribution falls within 3 standard deviation of the mean.

Evaluating

Given the mean as 110 and the standard deviation as 19 then;

68% of the scores will be between 110-19=91 & 110+19=129

95% of the scores will be between 110-2(19)= 72 & 110+2(19)=148

99.7% of the scores will be between 110-3(19)= 53 & 110 +3(19)= 167

Analysis

68% of the scores will lie between 91 and 129 points.

95% of the scores will lie between 72 and 148 points

99.7% of the scores will lie between 53 and 167 points.

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

step-by-step explanation: