Abox contains 4 white balls and 6 yellow balls a ball is drawn at random light from the box and is not replaced what is the probability that both balls are white

An

1/2

Step-by-step explanation:

There are 10 balls total and two balls are removed and not replaced so your fraction is 4/8 but you need to simplify it to 1/2

2/15

Step-by-step explanation:

p(first white)=4/10=2/5;

P(second white)=3/9=1/3;

P(both white)=2/5 x 1/3=2/15

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5

any options?

step-by-step explanation: