The height of an object thrown upward from the surface of a planet is given by the function s(t) = -2t2 + 28t, where t is the time in seconds and s(t) is the height in meters. what is the speed of the object at time t = 4?

The speed of the object at time, t=4 is

Step-by-step explanation:

The speed is calculated using the formula;

The distance covered by the object is given in terms of t, as

At time t=4, the distance covered by the object is;

The speed can now be calculated by substituting t=4 and distance 80 meters to obtain;

12 m/sec.

Step-by-step explanation:

The height of an object thrown upward from the surface of a planet is given by the function s(t) = - 2t² + 28t.

Here t = time

and s(t) = height in time t

Since the object has been thrown upwards under gravity so speed of ball will decrease with the time.

That means it we calculate rate of change in speed,

We can get the velocity at any moment of time.

So we will differentiate or find the derivative of the given expression.

s(t) = -2t² + 28t

V(t) = (-4t +28 )

Now at t = 4 velocity will be

V (4) = -4 × 4 +28 = -16 +28 = 12 m/sec.

The speed of the object is 12 meter per second.

step-by-step explanation:

i need to answer questions so i dont know but i think its the first one because it goes up but a consent rate

21.4 i did it already for s1

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