Here's a small fictitious drama with five actors: three people a, b and con death row; the governor, who has chosen one of them at random to be pardoned; and a warden in the prison, who knows the identity of the person the governor picked but isn't allowed to tell a, b or c who the lucky person will be. person a now speaks to the warden, as follows tell me the name of one of the other prisoners who's not going to be pardoned no harm done, since you won't be identifying the lucky person. let's agree on these rules: if b will be pardoned, you say c; if c will get the pardon, you say b; and if i'm the lucky person, you toss a 50/50 coin to decide whether to say b or c the warden thinks it over and says "b won't get the pardon." this is good news to a, because he secretly didn't believe that the warden's statement contains no information relevant to him he thinks that, given what the warden said, his chance for the pardon has gone up froo use bayes's theorem to show that a's reasoning is incorrect, thereby working out whether there was information in what the warden said that's relevant to a's probability of being pardoned.

the range of a function is the range of y-values for which it is defined, or exists. given that we are only looking at the y-values, we can already discount the first two answers as they deal with the domain of the function (range of x-values).

now, what we need to do is find the smallest and highest y-values for which the function is defined. if you'd like, you could take a ruler and start at the very bottom of the graph, find the lowest point, then move the ruler higher and higher until you reach the highest point. doing so either in your head or with an actual ruler, we can see that the lowest y-value is -5 and the highest y-value is -1.

the question now remains as to whether they are included in the range (fourth answer) or excluded (third answer). the key here is to recognise whether they are marked with an open or a closed circle. since both (-2, -5) and (2, -1) are marked with a closed circle, they are points that exist on the graph and are thus included in the range (note that if they were marked with an open circle like (4, -2) then that would signify that there is a break in the graph at that point).

thus, the fourth answer, (y | -5 ≤ y ≤ -1), is correct.

also note that usually it is good practice to scan your eye inbetween the highest and lowest point for any breaks in the graph - we do have one here at (4, -2), however -2 is still included in the range because there is another point that is included in the graph with the same y-value, ie. point (1, -2).

i hope that but if you require any further explanation don't hesitate to comment below.

step-by-step explanation:

step-by-step explanation:

the answer is that it is true