Identify the center and radius -10x+80+16y=x^2+y^2

Center: (-5,8)

Radius: 13

Step-by-step explanation:

The equation of the circle in center-radius form is:

Where the point (h,k)  is the center of the circle and "r" is the radius.

Subtract 16y from both sides of the equation:

Add 10x to both sides:

Make two groups for variable "x" and variable "y":

Complete the square:

Add inside the parentheses of "x".

Add    inside the parentheses of "y".

Add and to the right side of the equation.

Then:

We know that

Then, rewriting, you get that the equation of the circle in center-radius form is:

You can observe that the radius of the circle is:

And the center is:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180