If sin theta is negative and cot theta is positive, in which quadrant does theta terminate?
a)i b)ii c) iii d) iv

All you need to know is that:

So, if sin theta is negative and cot theta is positive, you're saying that you're looking at a point with negative y coordinate and such that

The ratio of two numbers is positive if and only if they have the same sign, so the cosine must by negative as well.

Saying that an angle has negative sine and cosine is the same as saying that the angle identifies a point on the unit circle where both x and y coordinates are negative.

So, if you look at the bullet list at the beginning, you'll see that the point is in the third quadrant.

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: