Its urgent

the 2006 value of a car was $18,000. in 2016, it was worth $4000. if the annual percent of decay has been constant, what is the annual percent of decay?

So the annual percent of decay is: 7.77%

Step-by-step explanation:

If the value of a car was $18000 in 2006, and in 2016 it was worth $4000 it means, it lose 77.77% of its value in 10 years.

To calculate the percentage of decay we use the rule of three:

If the price of the car in 2006 ($18000) represents 100%, then, how much does $4000 represents?

4000*100/18000 = %22.22

Now, we know that $4000 represents 22.22% the original value, so it lose 100% - 22.22% = 77.77% of its value.

So the annual percent of decay is: 77.77% / 10 = 7.77%

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

3.how is solving radical equations different than solving linear equations?

step-by-step explanation: