What is an equation of the line that passes through the point(-5,-5) and is parallel to the line 3x-5y=25

3x - 5y = 10

Step-by-step explanation:

Here's a fast but perfectly valid way to solve this problem:

Start with  3x-5y=25 ; replace that constant, 25, with C:

3x - 5y = C

Now plug in y = -5 and x = -5, obtaining:

3(-5) - 5(-5) = C

Then -15 + 25 = 10, and so C = 10, and:

3x - 5y = 10 is the desired equation of the new line.

the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.