30 points!
prove that am is perpendicular to bm

Extend the line segment AM until it touches AC, and call that intersection point P. Triangle AMP then forms a pair of similar triangles:

From this we know that angles MDP and AMP are congruent, and we already know MDP is a right angle so it follows that .

(You can ignore most of the labels in the image; I realized moments later after posting that the proof is much simpler than I originally thought)

by definition, an arc subtended by a central angle of some given measure has the same measure. so .

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier